According to survey records, 75.4% of women aged 20-24 have never been married. In a random sample of 25 young women aged 20-24, find the mean, variance and standard deviation for the number who are or who have been married.

mean = 6.15

variance = 4.637

standard deviation = 2.15

Step-by-step explanation:

It is given that 75.4% of women aged 20-24 have never been married.

We are interested in finding the mean, variance and standard deviation for the number who are or who have been married.

So the percentile of women who have been married is given by

The mean is given by

Where n is the sample size

Therefore, the mean is 6.15

The variance is given by

Therefore, the variance is 4.637

The standard deviation is given by

Therefore, the standard deviation is 2.15

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

5y

step-by-step explanation: