If f(t) = 13-
5*, what is the average rate of change of f(x) over the interval [1, 5]?

the answer is a. 72. but i cant answer with less than 20 characters so here's some random text talking about it.

hello 0xxbadwolfxx0,

2.6 x 10^9 is 2,600,000,000.

1.3 x 10^2 is 130

multiplying 130 and 2,600,000,000 would simply give you 200,000,000,000.

therefore, the answer would be d. 2.0 × 10^11.

i hope i ! warm regards, mae.