7. Defects in poured metal caused by contamination follows a Poisson distribution with average number of occurrences being 2 per cubic millimeter. What is the probability that there will be at least three defects in a randomly selected cubic millimeter of this metal

Step-by-step explanation:

If the number of defects in poured metal follows a Poisson distribution, the probability that x defects occurs is:

Where x is bigger or equal to zero and m is the average. So replacing m by 2, we get that the probability is equal to:

Finally, the probability that there will be at least three defects in a randomly selected cubic millimeter of this metal is equal to:

Where

So, P(0), P(1) and P(2) are equal to:

Finally, and are equal to:

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!