An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. Suppose that the mean income is found to be $18.5 for a random sample of 2253 people. Assume the population standard deviation is known to be $6.1. Construct the 98% confidence interval for the mean per capita income in thousands of dollars. Round your answers to one decimal place.

= ( $18.2, $18.8)

Therefore, the 98% confidence interval (a,b) = ( $18.2, $18.8)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $18.50

Standard deviation r = $6.10

Number of samples n = 2253

Confidence interval = 98%

z(at 98% confidence) = 2.33

Substituting the values we have;

$18.5+/-2.33($6.1/√2253 )

$18.5+/-2.33($0.128513644290)

$18.5+/-$0.299436791196

$18.5+/-$0.3

= ( $18.2, $18.8)

Therefore at 98% confidence interval (a,b) = ( $18.2, $18.8)

answer: 370

step-by-step explanation:

remember use pemdas! there are no parentheses or exponents so lets move onto the first part of the equation: multiplication and division. first, lets break the first part of the equation up into something easier using the distributive property. 28 * 12= (20 *12) + (8*12) you know that 20*12 is 240 and 8*12 is 96. add them and you get 336. then, lets solve the last part of the equation (the last part of pemdas is addition and subtraction). 336 plus 34 is 370. hope this !