Yearly healthcare expenses for a family of four are normally distributed with a mean expense equal to $3,000 and a standard deviation equal to $500. A sample of 36 families was selected and the mean and standard deviation were was found to be $3250 and $400 respectively. What is the probability of healthcare expenses in the population being greater than $4,000?

The probability of healthcare expenses in the population being greater than $4,000 is 0.02275.

Step-by-step explanation:

We are given that yearly healthcare expenses for a family of four are normally distributed with a mean expense equal to $3,000 and a standard deviation equal to $500.

Let X = yearly healthcare expenses of a family

The z-score probability distribution for the normal distribution is given by;

                            Z  =    ~ N(0,1)

where, = population mean expense = $3,000

            = standard deviation = $500

Now, the probability of healthcare expenses in the population being greater than $4,000 is given by = P(X > $4,000)

     P(X > $4,000) = P( > ) = P(Z > 2) = 1 - P(Z 2)

                                                                  = 1 - 0.97725 = 0.02275

The above probability is calculated by looking at the value of x = 2 in the z table which has an area of 0.97725.

2/3

step-by-step explanation:

the slope of a line is equal to the rise/run. in this case the line rises 2 units for every +3 units it moves

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: