The diagram shows a circle, centre O.
Work out the value of a.
BCO=41 degrees

a = 49°

Step-by-step explanation:

OB = OC ( both radii of the circle ), thus

Δ BOC is isosceles and the base angles are congruent, that is

∠ OBC = ∠ OCB = 41° , so

∠ BOC = 180° - (2 × 41)° = 180° - 82° = 98°

The angle on the circumference BAC is half the angle at the centre for angles subtended on the same arc , thus

a = 0.5 × 98° = 49°

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

im not sure

step-by-step explanation: