A box of cereal must weigh more than 629 g and less than 633 g to pass inspectionThe box in which the cereal is packaged weighs 5 g What are the possible weights for the cereal only?

625g ,626g ,627 g

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The weight of the cereal (x) plus the weight of the box (5) must be higher than 629 and less than 633.

Mathematically speaking:

629<5+x<633

Solving for x:

629 <5+x

629-5 <x

624<x

5+x<633

x<633-5

x<628

624<x<628

So, the weight of the cereal only must be higher than 624g and less than 628g.

The possible weights are  

625g ,626g ,627 g

Feel free to ask for more if needed or if you did not understand something.  

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step-by-step explanation:

36 girls

step-by-step explanation:

the 48 boys is 4 parts of the ratio

divide 48 by 4 to obtain one part of the ratio

= 12 ← 1 part of the ratio

3 parts = 3 × 12 = 36 ← number of girls