(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y
{-2, 1}
{-2, 3}
{}
...
Mathematics, 22.06.2020 20:57, juliomeadaptas
(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y
{-2, 1}
{-2, 3}
{}
Answers: 3
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