you have a 5-inch by 7-inch picture that you framed. When you hung the picture, you found that the entire area is 69.56 in. What is the width of the frame?

d. 2.4 in

Step-by-step explanation:

So initially w/o frame the area was 5 x 7 = 35 sq in.

Now we have to add the width of the frame to both dimensions.

(5+w)(7+w) = 69.56 sq in

35 + 7w + 5w + w² = 69.56

w² + 12w + 35 = 69.56

w² + 12w - 34.56 = 0

I use the quadratic formula to solve this (x = -b±√b²-4ac / 2a). I cheat by using a quadratic program on the calculator :,)

w = 2.4

w = -14.4

Since we can't have a negative width, the answer must be w = 2.4 inches.

You can also just plug the answer choices one-by-one into the calculator with guess-and-check because this is multiple choice.

 d) 2.4 inches

Step-by-step explanation:

Let x represent the width of the frame

Then the area of the frame is:

(x + 5)(x + 7) = 69.56

Rewrite it in Standard form of a quadratic equation:

x² + 12x + 35 = 69.56

x² + 12x - 34.56 = 0

Use Quadratic Formula to solve for x:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

it’s supposed to be -4+45=41

step-by-step explanation: