Given cot ø = 4/3. Find the other two reciprocal trigonometic ratios. 1) scs 2) sec

csc ø = 5/3 ; sec ø = 5/4

Step-by-step explanation:

cot ø = adj/opp

adj = 4

opp = 3

after that, we must find the hypotenuse by using phytagoras theorem

hpy² = adj² + opp²

hpy² = 4² + 3²

hpy² = 25

hpy = 5

now let's find the other

csc ø (not scs) = hyp/opp = 5/3

sec ø = hyp/adj = 5/4

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.