Write a rule for the nth term of the sequence 15, 19, 23, 27

aₙ= 4n+11

Step-by-step explanation:

the sequence 15, 19, 23, 27

is AP with the first term 15 and

the common difference 19-15=23-19=27-23= 4

aₙ= a₁+(n-1)d

aₙ= 15+(n-1)*4= 15+4n- 4= 4n+11

aₙ= 4n+11

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.