William, Nancy, and Edgar met at the lodge at 8 AM. William began hiking west at 3 mph. At 10 AM Nancy began hiking north at 5 mph and Edgar went east on a three wheeler at 12 mph. At what time was the distance between Nancy and Edgar 10 miles greater than the distance between Nancy and Willam? : AM/PM

12:00 AM

Step-by-step explanation:

Taking the lodge as the center of the coordinate system, the position of each person is:

William: 6+3*t

Nancy: 5*t

Edgar: 12*t

where t is in hours after 10:00 am

Between the positions of William and Nancy, a right triangle is formed, where their distance is the hypotenuse.

WN = √[(5*t)² + (6+3*t)²]

Similarly, Between the positions of Nancy and Edgar:

NE = √[(5*t)² + (12*t)²]

If the distance between Nancy and Edgar is 10 miles greater than the distance between Nancy and Willam, then

NE = WN + 10

√[(5*t)² + (12*t)²]  = √[(5*t)² + (6+3*t)²] + 10

With the help of the graph of this equation, we find that t = 1.95 or approximately 12:00 AM

the answer is c 150

step-by-step explanation:

step-by-step explanation: