By how much does a a^3-2a exceed a^2 + a -6

a³ - a² - 3a+ 6

Step-by-step explanation:

we are asked by how much does (a³-2a) exceed (a²+a-6)

in other words, we are being asked to find the difference between the 2 terms above.

Mathematically we are asked to find:

(a³-2a) - (a²+a-6)    (expand parentheses by distribution property)

=(a³-2a - a²- a + 6)

= a³ - a² - 3a+ 6    (answer)

the correct answer is option c.   3

step-by-step explanation:

points to remember

equation of the line with coordinates (x₁, y₁) and (x₂, y₂) is given by,

slope m = (y₂ - y₁)/(x₂ - x₁)

from the figure we can see a line with two coordinates given

to find the slope of given line

here   (x₁, y₁)   = (-1, -1 ) and (x₂, y₂) = (1, 5)

slope m = (y₂ - y₁)/(x₂ - x₁)

  = (5 - -1)/(1 - -1)

  = (5 + 1)/(1 + 1)

  = 6/2 = 3

therefore the correct answer is option c.   3

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!