which of the following are solutions to the quadratic equation check all that apply 2x ^ 2 + 6x - 10 equals x ^ 2 + 6

c and F

Step-by-step explanation:

2x² + 6x - 10 = x² + 6

2x² - x² + 6x - 10 - 6 = 0

x² + 6x - 16 = 0

(x + 8)(x - 2) = 0

x = -8

x = 2

so C and F

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)