Please help asap calculate the slope of the line through the points (6,-8) and (3,-4). a. Write the equation of the line

b. Is the point (-3,4) on the line you found in part a?

y = -4/3x + 0. Yes, that point lies on the line

Step-by-step explanation:

Use this equation, Δy/Δx and this one, y = mx + b. Or, change in the y value divided by the change in the x value.

-4 + 8 = 4

3 - 6 = -3

The slope, m, is -4/3. Now solve for b by plugging in the slope.

. B is equal to 0

To see if that point lies on the function, plug it in the equation and see if it is true. Multiply -4 x -3 to get 12, divide by 3 to get 4, then add 0. The equation says that 4 = 4, which is infact true

y=-4x/3

the point (-3,4) is on the line y= -4x/3

Step-by-step explanation:

the points (6,-8) and (3,-4)

a) (y- y1)/(y2- y1)=(x- x1)/(x2- x1)

(y+8)/(-4+8)=(x-6)/(3-6)

(y+8)/4=(x-6)/(-3)

-3y-24=4x-24

So, y=-4x/3

b) (-3; 4)

4= -4*(-3)/3

4=4 it is true,

the point (-3,4) is on the line y= -4x/3

m∠vru = 80°

m∠urw = 15°

step-by-step explanation: