6x +7y=-46 3x-2y=32 solve this system of linear equations

Hello

We have two equations and need to find x and y

(1) 6x+7y=-46

(2) 3x-2y=32

multiply (2) by 2 it gives

(2') 6x-4y=64

(1) - (2') gives

6x+7y-6x+4y=-46-64 = -110

so 11y = -110

y = -10

replace in (2) it gives

3x+20=32

3x=12

x = 12/3 = 4

the solution is (4,-10)

do not hesitate if you need further explanation

if you like my answer, tag it as the brainliest :-)

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.