Based on historical data, your manager believes that 36% of the company's orders come from first-time customers. A random sample of 195 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.34 and 0.49

And the distribution for the sample proportion is given by;

And we can find the mean and deviation for the sample proportion:

[te]\mu_{\hat p}= 0.36[/tex]

And we can use the z score formula given by:

And we can use the normal distribution table and we got:

Step-by-step explanation:

For this case we know that the sample size is n =195 and the probability of success is p=0.36.

We want to find the following probability:

And the distribution for the sample proportion is given by;

And we can find the mean and deviation for the sample proportion:

And we can use the z score formula given by:

And we can use the normal distribution table and we got:

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

y > 1/3x

y < = -x + 4

hope this : )