A line goes through the origin and the point (6, 14). The point (2, y) is also on the line. Calculate y and justify that your value is correct

Step-by-step explanation:

The key here is knowing that the equation of the line that passes through these points is same

Thus having (6,14) and (0,0), the slope is as follows;

m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3

Now we can use this slope here to get the value of y in the question

All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)

That would be;

7/3 = y-14/1-6

7/3 = y-14/-5

cross multiply;

-35 = 3(y-14)

-35 = -3y + 42

-3y = -35-42

-3y= -77

y = -77/3

y = 77/3

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square