The complex solution to a quadratic equation is below. Write this solution in standard form, a+bi, where a and b are real numbers. What are the values of a and b.

a = -6 and b = 3√2

Step-by-step explanation:

Given the complex solution below;

x = (-24±√-288)/4

Re writing in the standard format a,+bi

x =( -24±√144×√2×√-1)/4

In complex notation, i = √-1

x = (-24±√144×√2×i)/4

x = ( -24±12×√2i)/4

x = -24/4±12√2i/4

x = -6±3√2i

Comparing the resulting complex number with a+bi

a = -6 and b = 3√2

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180