Toby goes on holiday to Geneva, Switzerland. In Geneva, Toby sees a watch costing 193.75 CHF (Swiss Francs). In Manchester, an identical watch costs £145. Given that £1=1.55CHF a) In which city is the watch cheaper. b) By how much is it cheaper (in £) i need help on part b , please help;(

The watch is cheaper in Geneva, Switzerland by a value of £20

Step-by-step explanation:

To get the city in which the watch is cheaper, what we need to do is to express the price of the watch in the same currency.

Since pounds is also used in the b part of the question, it would be easier working with it.

In Geneva, the price of the watch is 193.75 CHF

from our conversion formula;

£1 = 1.55 CHF

£x = 193.75 CHF

We cross multiply to get the value of x

(193.75 * 1)/1.55

= 193.75/1.55 = £125

We can see that the watch costs less in Geneva and higher in Manchester

By how much is it cheaper?

We can calculate this by subtracting the value in Geneva from the value in Manchester

That would be 145-125 = £20 cheaper

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

150.6

all i did was i multiplied 5.02 by 30