A manufacturer of cheese filled ravioli supplies a pizza restaurant chain. Based on data collected from its automatic filling process, the amount of cheese inserted into the ravioli is normally distributed. To make sure that the automatic filling process is on target, quality control inspectors take a sample of 25 ravioli and measure the weight of cheese filling. They find a sample mean weight of 15 grams with a standard deviation of 1.5 grams. What is the standard deviation of sample mean

And the standard deviation for the sample mean would be given by:

Step-by-step explanation:

For this case we know that the amount of cheese inserted into the ravioli is normally distributed. And we have the following info given;

the sample mean

the sample deviation

the sample size

And for this case we know that the sample size is large enough in order to apply the central limit theorem and the distribution for the sample mean would be given by:

And the standard deviation for the sample mean would be given by:

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours

answer is  

c.

36

step-by-step explanation: