Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = t, y = e−4t, z = 5t − t5; (0, 1, 0) x(t), y(t), z(t) = t,1−4t,5t Illustrate by graphing both the curve and the tangent line on a common screen.

Step-by-step explanation:

At the point (0, 1,0) t = 0

Find the tangent vector:

The tangent vector for all points is

The vector equation of the tangent line is

The parametric equation for this line are

i would say c is the best answer, hope it's right!

good luck! =)

cutie~