Mathematics, 19.06.2020 04:57, hehefjf8610
A company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x)=14,000ln(0.01x+1). Use the differential to approximate the change in revenue fro the sale of one more doghouse if 110 doghouses have already been sold. (Round to nearest cent as needed)
Answers: 3
![\dfrac{dR}{dx}=\dfrac{d}{dx}[14,000\cdot \text{ln}(0.01x+1)]\\\\\\\dfrac{dR}{dx}=14,000\dfrac{d}{dx}[\text{ln}(0.01x+1)]\\\\\\\dfrac{dR}{dx}=14,000\cdot\dfrac{1}{0.01x+1}\cdot \dfrac{d}{dx}(0.01x+1)\\\\\\\dfrac{dR}{dx}=14,000\cdot\dfrac{1}{0.01x+1}\cdot 0.01\\\\\\\dfrac{dR}{dx}=\dfrac{14,000}{x+100}](/tpl/images/0689/7334/4d340.png)
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A company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x)=14,0...
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