If you toss 3 dices, what is the chance to get at least one 3?

0.4213

Step-by-step explanation:

For "at least" questions, it is useful to calculate the probability of that event not happening, In this case, the probability of not getting one three (or any specific number). It is quite obvious that for one dice you have a 5/6 chance of not getting a three. For three the probability of not getting a three would then be:

5/6⋅5/6⋅5/6=125/216=0.5787

So the opposite (getting at least one three) would be 1 minus that or 1 - 0.5787 = 0.4213

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )