A random sample of 1,000 couples was asked the question, "How many children presently reside in your household? Number of Children Frequency

0

225

1

112

2.

460

3

101

4

68

5 or more

34

What number of children occurred the most frequently? Calculate this percent. (2 points)

O 2.54%

2.217%

2.46%

O 5 or more, 3.4%

2, 46%

Step-by-step explanation:

==>Given:

Number of Children=>Frequency

0=>225

1=>112

2=>460

3 =>101

4=>68

5 or more=>34

Total no. of couples surveyed=>1000

==>REQUIRED:

No./% of children with the highest frequency.

==>SOLUTION:

The no. of children that occurred the most is 2, having a frequency of 460.

The % = 460 ÷ 1000 × 100

= 0.46 × 100

= 46%

Our answer is 2, 46. The number of children 2, which occurs most frequently has a percentage of 46.

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24