Lincoln has 16 pins in one box and 17 pins in another box. He is hanging posters with the pins. Lincoln uses 4 pins to hang each posted. What is the total number of posters Abe can hang with the pins?

8 posters

Step-by-step explanation:

From the question, we are informed that Lincoln has 16 pins in one box and 17 pins in another box and that he uses 4 pins to hang each posters posted. The total number of posters he can hang with the pins goes thus:

We should first calculate the total number of pins he has.

= 16 + 17 = 33 pins

Since he uses 4 pins to hang a poster, we then divide 33 pins by 4.

= 33 ÷ 4

= 8.25

This means that he can hang 8 posters with the pin

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb