For each system of equations, drag the true statement about its solution set to the box under the system. HURRY PLEASE!

Ok, some theory first:

If we have more variables than linear independent equations, then we have infinite solutions.

If we have the same number of linearly independent equations and variables, we can have a unique solution or no solution.

we have no solution in cases where:

y = x + 3

y = x - 3

this leads to:

x + 3 = x - 3

+3 = -3

so this system has no solutions.

The first system of equations is:

y = x + 5

y = 2x + 5

Now, you can see that we have 2 variables, and 2 linear independent equations, this means that we have only one solution for this system

So here we have "One solution, the graph of these lines should intersect at one point" and the point is (0, 5)

The second system is:

y = x + 5 + x = 2x + 5

y = 2x+ 5

Both equations are the same, so here we have 2 variables and only one equation, this means that we have infinite solutions for this system.

here the correct option is the one that says "infinitely many solutions, both right side and left side are equivalent expressions"

false

step-by-step explanation:

rulers and compasses arent required in order to bisect an angle because when bisecting angles, you're making a "half circle" and considering in order to bisect an angle it wouldn't be straight, you wouldn't need either of the two

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.