Mathematics, 18.06.2020 20:57, myohmyohmy

Need some help with number word problems, tysm if you do :)

Answers: 3

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answered: danielburke24

Read below

Step-by-step explanation:

x is always the smaller number

y is always the larger number

underlined means it's the question

bolded means it's the answer

One number is 6 times as large as another. Their sum is 42. Find the numbers.

The numbers need to fit the criteria:

6x=yx+y=42

A. 6+36=42 (correct)

B. 7+42=49 (incorrect)

C. 7+35=42 (incorrect because it doesn't follow the 1st rule)

D. 6+42=48 (incorrect)

Only A. 6, 36 fits the criteria.

One number is 3 less than another. Four times the smaller is 4 more than 3 times the larger. Find the numbers.

The numbers need to fit the criteria:

x+3=y4x-4=3y

4+3=7

12-6≠21 (incorrect)

7+3=10

28-3≠30 (incorrect)

13+3=16

52-4=48 (correct)

9+3≠13 (incorrect)

Only C. 13, 16 fits the criteria.

One number is 4 less than another. Five times the smaller is 3 less than 4 times the larger. Find the numbers.

The numbers need to fit the criteria:

x+4=y5x+3=4y

13+4=17

65+3=68 (correct)

-23+4= -19

-115+3≠ -76 (incorrect)

17+4=21

85+3≠84 (incorrect)

-11+4+ -7

-35+3≠ -33 (incorrect)

Only A. 13, 17 fits the criteria.

The sum of two numbers is 23. When three times the smaller is subtracted from the larger, the result is 3. Find the numbers.

The numbers need to fit the criteria:

x+y=23y-3x=3

5+18=23

18-15=3 (correct)

8+15=23

15-24≠3 (incorrect)

-13+36=23

36+39≠3 (incorrect)

-5+28=23

28+15≠3 (incorrect)

Only A. 5, 18 fits the criteria.

The sum of two numbers is 26. When twice the smaller is subtracted from the larger, the result is 2. Find the numbers.

The numbers need to fit the criteria:

x+y=26y-2x=2

8+18=26

18-16=2 (correct)

9+17=26

17-18≠2 (incorrect)

7+19=26

19-14≠2 (incorrect)

6+20=26

20-12≠2 (incorrect)

Only A. 8, 18 fits the criteria.

answered: Guest

$5.25t + 2 = 16.5t + 11$
Can someone explain how to do this plz?

answered: Guest

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

Point z is equidistant from the sides of δrst. which must be true? ctzaszaszzsb

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