Find the terminal point on the unit circle determined by 2pi/3 radians

Using the unit circle, it is found that the terminal point for an angle of is given by:

The terminal point on the unit circle for an angle of is given by:

is on the second quadrant, as . Hence, the sine is positive and the cosine is negative.

To find the equivalent angle on the first quadrant, we subtract by , hence:

Hence, the sine and the cosine are:

Then, the point is:

A similar problem is given at link

Terminal point determined by 2π/3 is

Step-by-step explanation:

Unit circle can be defined a as circle which has a radius of 1.

We have to find the point on the circle which corresponds to 2π/3.

For ease, lets convert radians into degrees.

2π/3 = 2(180)/3 = 120°

Let make a line AE at 120° from the origin such that it intersects the circle at point E.

Draw a perpendicular from point E to F. such that we get a right angled triangle AFE.

(DIAGRAM ATTACHED BELOW)

We can see that:

<FAE + 120° = 180°

<FAE = θ = 60°

We have to find the base and perpendicular of the formed triangle, which shows that terminal point

Hypotenuse = radius = 1

cos θ = Base/Hypotenuse

(cos 60) = Base/1

Base = 1/2 where x is in negative direction

sin θ = Perpendicular/Hypotenuse

sin 60 = Perpendicular/1

Perpendicular = (√3) /2

So the terminal point is

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

step-by-step explanation:

deez nut