A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time t=0 is v(0)=13. What is its position at time t=5?

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

Velocity:

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

Position:

Since s(0) = 3

What is its position at time t=5?

This is s(5).

It's position at time t = 5 is 593.

1

step-by-step explanation:

it's the only multiple of both and the least

is this part of a question or something