Assume that equation 1, f(x) = x2 (the black parabola), is the parent quadratic function. Equation 2, g(x) = (x − c)2 (the blue parabola), and equation 3, h(x) = x2 + d (the red parabola), are transformations of the parent function for various values of c and d. What happens as you change the values of c and d?

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18