What is the equation of the line that passes through (4, -1) and (-2, 3)? 2 x+3y- 5 = 0
-2 x+3y- 5 = 0
2x-3y-5=0

Step-by-step explanation:

(3+1)/(-2-4)= 4/-6= -2/3

y + 1 = -2/3(x - 4)

y + 1 = -2/3x + 8/3

y = -2/3x + 5/3

Multiply both sides by 3

3y = -2x + 5

2x + 3y = 5

2x + 3y - 5 = 0

answer is A

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice