F(x)=(x-3)^2+5 plot the vertex and the axis of symmetry of this function.

The vertex is located at (3,5)

The axis of symmetry is x = 3

The plot is in the image attached

Step-by-step explanation:

First we need to find the vertex of the quadratic function. We can find the x-coordinate of the vertex using the formula:

x_v = -b / 2a

Where 'a' and 'b' are coefficients of the quadratic equation in the model:

ax^2 + bx + c = 0

Then we need to expand the terms of f(x):

f(x) = (x-3)^2 + 5

f(x) = x^2 - 6x + 9 + 5

f(x) = x^2 - 6x + 14

So we have a = 1 and b = -6

Then the x-coordinate of the vertex is:

x_v = 6 / 2 = 3

We can use this value in f(x) to find the y-coordinate of the vertex:

f(x_v) = 3^2 - 6*3 + 14 = 5

So the vertex is located at (3,5)

The axis of symmetry is the vertical line traced in the vertex, so it is x = 3

The plot is in the image attached. The circle at (3,5) is the vertex, and the blue line is the axis of symmetry.

answer: finding the extract measurements and knowing the points

step-by-step explanation:

h/o/e/s mad

step-by-step explanation:

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