Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.2 chocolate chips per cookie and a standard deviation of 2.6 chocolate chips per cookie. Find Upper P 5 and Upper P 95. How might those values be helpful to the producer of the chocolate chip cookies?

Percentile 5

And if we solve for a we got

Percentile 95

And if we solve for a we got

Step-by-step explanation:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

Where and

We want to find the percentiles 5 and 95 for this case.

Percentile 5

For this part we want to find a value a, such that we satisfy this condition:

  (a)

  (b)

We want to find a percentile with 0.95 of the area on the left and 0.05 of the area on the right it's z=-1.64. On this case P(Z<-1.64)=0.05 and P(z>-1.64)=0.05

Using this condition we got:

Replacing we got:

And if we solve for a we got

Percentile 95

And if we solve for a we got

x=12 units bd= 10 units

step-by-step explanation:

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people