%) 1.3.27 Question Help
The length of a new rectangular playing field is 6 yards longer than double the width. If the perimeter of the rectangular playing field
is 312 yards, what are its dimensions?
The width is yards

Width of field  = 50 yards

Length of Yards =  106 yards

Step-by-step explanation:

Let the width of field be x yards

given that "The length of a new rectangular playing field is 6 yards longer than double the width"

Length of Yards= 2*width of field + 6 = 2x+6 yards

perimeter of the rectangular playing field  = 312 yards

We know that perimeter of rectangle is given by 2(length + width ).

Since field is rectangular then

2(length + width ) = 312

2(x+2x+6) = 312

=> 3x+6 = 312/2 = 156

=> 3x = 156 - 6 = 150

=> x = 150/3 = 50

Thus,

Width of field is x = 50 yards

Length of Yards=  2x+6 yards = 2*50+6  yards = 106 yards

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!