The spinner has eight spaces of equal size. What is the mathematical probability of the pointer's stopping in the space marked 1? If you spin the pointer 40 times, how many times would you expect it to stop on 1?

The probability that the pointer stops on 1 is 1/8, since there are 8 sections.

If you spun it 40 times, you would expect it to land on 1 5 times.

Step-by-step explanation:

There are equal pieces, so the probability of landing on each is the same : 1/8

To find the amount of times you would expect it to land on 1 if you spun it 40 times, simply multiply the probability by 40. 40 * 1/8 = 5.

Hope this helps :)

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.