Nashan randomly chooses 6 positive integers a, b, c, d, e, f. Find the probability that 2 ^a + 2^b + 2^c + 2^d + 2^e + 2^f is divisible by 5.

0.20

Step-by-step explanation:

we have that:

a number is only divisible by 5 if:

the unit digit of the number is 0 or 5.

As we have:

2^a + 2^b + 2^c + 2^d + 2^e + 2^f = X

we can never have 5 as the last digit, so we only can have a zero as the last digit.

Now, we know that

2^a + 2^b + 2^c + 2^d + 2^e + 2^f can only end with even numbers, if we assume the same probability for all of them, we have 0, 2, 4, 6, 8

5 even numbers, and the sum will be divisible by 5 only if the last number is a zero, then the probability having a zero in the last number is equal to the number of times that zero appears in that set, divided the total number of elements in that set.

p = 1/5 = 0.20

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

answer: howdy

step-by-step explanation: