The sum of 3 consecutive odd integers is 411. State the values of the integers.

Represent 3 consecutive odd integers as follows.

X ⇒ first odd integer

X + 2 ⇒ second odd integer

X + 4 ⇒ third odd integer

Since their sum in this problem is 411, x + (x + 2) + (x + 4) = 411.

Now combine like terms to get 3x + 6 = 411.

No subtract 6 from both sides to get 3x = 405.

Now divide both sides by 3 and x = 135.

So x + 2 would be 137 and x + 4 would be 139.

So our consecutive odd integers are 135, 137, and 139.

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