1.Suppose a group of 24 people bought tickets to the American Kennel Club Museum of the Dog. Tickets cost $15 each for adults, $10 each for students, and $5 each for children under age 12. There were twice as many adults as children under age 12. If the total cost of the tickets was $260, how many tickets were purchased for children under age 12? * 4 tickets 6 tickets 12 tickets 8 tickets

4 tickets for children under 12.

Step-by-step explanation:

A is the number of adults, S is the number of students and C is the number of children.

We have the equations:

1)  A + S + C = 24.

2) A = 2*C

3) A*$15 + S*$10 + C*$5 = $260

So we have 3 equations and 3 variables.

First, we can replace A in both of the other equations.

1) 2*C + S + C = 24

   S + 3*C = 24

and

3)  (2*C)*$15 + S*$10 + C*$5 = $260

    C*($30 + $5) + S*$10 = $260

    C*$35 + S*$10 = $260

Now, we should isolate S in the first equation, and get:

1) S = 24 - 3*C

now we can replace it on the other equation:

3) C*$35 + S*$10 = $260

   C*$35 + (24 - 3*C)*$10 = $260

   C*($35 - $30) + $240 = $260

   C*$5 = $20

    C = 20/5 = 4

So we have 4 children.

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: