What is the equation of the line that passes through (1, 2) and is parallel to the line whose equation is 2x + y - 1 = 0?

y= -2x +4

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient.

Let's rewrite the equation of the given line in the form of y=mx+c, so that we can obtain it's gradient.

2x +y -1= 0

y= -2x +1

Thus gradient of the line is -2.

subst. m= -2 into the equation:

y= -2x +c

To find the value of c, substitute a coordinate.

When x=1, y=2,

2= -2(1) +c

2= -2 +c

c= 2 +2

c= 4

Thus, the equation of the line is y= -2x +4.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)