A car insurance company has determined that 8% of all drivers were involved in a car accident last year. If 14 drivers are randomly selected, what is the probability of getting 3 or more who were involved in a car accident last year?

0.0958

Step-by-step explanation:

Percentage involved in accident = 8% = 0.08

Number of drives selected = 14

Probability that 3 or more who were involved in a car accident last year?

P(x>=3) = P(x=3) or P(x>3)

Similarly;

P(x>=3) = 1-P(0<= x <=2)

P(x>=3) = 1-P(0<= x <=2)

Using the binomial probability calculator :

Cummulative probability :

P(X >= x) = 0.09583481948

= 0.0958

correct answer:

b.(19,-2)