The percent rounded to the nearest tenth. Question #1:
What is the probability that the family will have exactly 3 boys?_=0.__x 100 =
Final
%
Question #2:
What is the probability that the family will have exactly 2 boys and 1 girl?___= 0.__x 100 =
Final
%
Question #3:
What is the probability that the family will have at least 2 girls?_=0._x 100 =
%
Final

Help this is my exam but I don’t understand it

Step-by-step explanation:

If you don't use specific percents of probability of either gender being born written by doctors (boy is like 0.425 or something, I can't remember for sure) and you didn't specify so,

I will say that the probability of a boy being born is 1 out of 2 and a girl being born is 1 out of 2 : thus the percent of either boy or girl being born that time is 0.5 or 50%

1)

the probability that the family will have exactly 3 boys is

P(boy)*P(boy)*P(boy)=1/2*1/2*1/2:

0.5*0.5*0.5=0.125

now, lets convert to percent:

0.125=12.5%

2)

the probability that the family will have exactly 2 boys and 1 girl is:

P(boy)*P(boy)*P(girl)=1/2*1/2*1/2:

0.5*0.5*0.5=0.25*0.5=0.125

now, lets convert to percent:

0.125=12.5%

3)

The probability that the family will have at least 2 girls is:

P(girl)*P(girl)=1/2*1/2:

0.5*0.5=0.25

now, lets convert to percent:

0.25=25%

Does this help? If there are specific decimals on each, then do the same thing only with them

answear:

a

step-by-step explanation: a

4th option is correct xy=-10

if this was to u plzz mark me the brainliest