Overbooking flights is a common practice of most airlines. A particular airline, believing that 3% of passengers fail to show for flights, overbooks (sells more tickets than there are seats). Suppose that for a particular flight involving a jumbo-jet with 267 seats, the airline sells 278 tickets. Question 1. What is the expected number of ticket holders that will fail to show for the flight

The expected number of ticket holders that will fail to show for the flight is 8.34.

Step-by-step explanation:

For each passenger, there are only two possible outcomes. Either they fail to show up to the flight, or they do not. The probability of a passenger not showing up is independent of other passengers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

3% of passengers fail to show for flights

This means that

The airline sells 278 tickets

This means that

What is the expected number of ticket holders that will fail to show for the flight

The expected number of ticket holders that will fail to show for the flight is 8.34.

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.