1 of 5 A fair spinner has 9 equal sections: 3 red, 4 blue and 2 green.
It is spun twice.
What is the probability of getting green both times?

4/81

Step-by-step explanation:

The probability of getting green is 2/9.

The probability getting green twice is (2/9)² = 4/81.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

step-by-step explanation: