Which equation has two real solutions? A. x2 = –100
B.5x2 = 1
C.6x2 + 17 = 11
D.7(x2 + 6) = 42

Step-by-step explanation:

A.x² = –100

This equation has no solution because x² is always positive.

B.5x² = 1

then x² = 1/5

then x = 1/(√5) or x = -1/(√5)

C.6x² + 17 = 11

then 6x² = 11 - 17 = -6

then x² = -6/6 = -1  

This equation has no solution because x² is always positive.

D.7(x + 6) = 42

then x + 6 = 42/7 = 6

then x = 6 - 6 = 0

:)

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent