Classify the random variables below according to whether they are discrete or continuous. a. The number of people in a restaurant that has a capacity of 100.b. The height of a randomly selected giraffe. c. The square footage of a house. d. The number of light bulbs that burn out in the next week in a room with 10 bulbs. e. The number of points scored during a basketball game.

a) Discrete

b) Continuous

c) Continuous

d) Discrete

e)Discrete

Step-by-step explanation:

Continuous:

Real numbers, can be integer, decimal, etc.

Discrete:

Only integer(countable values). So can be 0,1,2...

a. The number of people in a restaurant that has a capacity of 100.

You cannot have half a person, for example.

The possible number of people in the restaurant are 0, 1, 2,..., 100. So this variable is discrete.

b. The height of a randomly selected giraffe.

The giraffe can have half a meter, for example. That is, the height can be a decimal number. So this variable is continuous

c. The square footage of a house.

You can have half a square, for example. So this variable is continuous.

d. The number of light bulbs that burn out in the next week in a room with 10 bulbs.

Possible values: 0 bulbs, 1 bulb, ..., 10 bulbs

Only countable values.

So discrete

e. The number of points scored during a basketball game.

0 points, 1 point, 2 points, 10 points, ...

There are no half points in basketball.

So discrete

constant of proportionality = 3 and the equation is c = 3p.

step-by-step explanation:

c = kp   where c = amount of caffeine in mg., p = oz of pepsi and k is the constant of proportionality.

substituting the values given:

24 = 8k

k = 3.

the same value of k will be obtained if we substitute the other given values.

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt