The upper-left coordinates on a rectangle are (-6,0)(−6,0)left parenthesis, minus, 6, comma, 0, right parenthesis, and the upper-right coordinates are (-4,0)(−4,0)left parenthesis, minus, 4, comma, 0, right parenthesis. The rectangle has an area of 121212 square units. Draw the rectangle on the coordinate plane below.

Given : The upper-left coordinates on a rectangle are (-6,0) and upper-right coordinates are (-4,0) . rectangle has an area of 12 square units

To find : other Coordinates

Solution:

upper-left coordinates  = ( - 6 , 0)

upper-right coordinates = ( - 4, 0)

Length  = 2

slope = 0

Area = 12

=> width = 12/2  = 6

Slope of other lines = 1/0

=> lines are x  = -6      &  x  = - 4

y coordinate can be  then

6  = √(-6 - 6)² + ( y - 0)²  = √(-4 - 4)² + ( y - 0)²

=> 6 = √y²

=> 6 = ±y

but point should be below as given point are upper

Hence  other coordinates are  ( - 6 , - 6)   & ( - 4  , - 6)

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