There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen? Does this represent an independent or dependent event? Explain

3.1%, dependent event

Step-by-step explanation:

We have that vowel are 5, it is from A, E, I, O, U therefore the probability of drawing a vowel is:

5/26

since there are a total of 26 options to choose from. Then, when selecting that, we are left with 25 options and 4 vowels, therefore the probability would be:

4/25

Therefore the final probability is:

5/26 * (4/25) = 0.031

In other words, selecting a vowel and then another (without replacement) the probability is 3.1%

The events are dependent, since the first event affects the second event, since the number of vowels and the number of total options are reduced.

entering that problem on the tube might get you an answer

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!