The slope of a line is –2 and its y-intercept is (0, 3). what is the equation of the line that is parallel to the first line and passes through (2, 2)? a. y=4/3x - 3/2 b. 6x-4y=-8 c. y=3/4x 1 d. 4x – 2y = –12

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

here is a big fat