Mathematics, 12.06.2020 16:57, zoeyjorschumb17

Jim’s work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFraction) = 2 (StartFraction 3 times 3 times 3 Over 5 EndFraction) = 2 (StartFraction 27 Over 5 EndFraction) = StartFraction 54 Over 5 EndFraction

Which statement best describe Jim’s first error?
He did not multiply Three-fifths by 2 before applying the power.
He did not apply the power to the denominator of Three-fifths.
He did not evaluate 33 correctly.
He did not multiply StartFraction 27 Over 5 EndFraction by 2 correctly.

Answers: 3

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Jim’s work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFract...